Calculate how much energy is stored in a 17μF capacitor when it is charged to a potential
difference of 200 V
energy=1/2 C v^2=.5*17e-6*4e4=.34 joule check that.
Thank you so much
To calculate the energy stored in a capacitor, we can use the formula:
E = (1/2) * C * V^2
Where:
E = energy stored in the capacitor
C = capacitance of the capacitor
V = potential difference across the capacitor
Given that the capacitance (C) is 17μF (microfarads) and the potential difference (V) is 200 V, we can substitute these values into the formula:
E = (1/2) * (17 * 10^-6 F) * (200 V)^2
First, let's calculate (1/2) * (17 * 10^-6 F):
(1/2) * (17 * 10^-6 F) = 8.5 * 10^-6 F
Now, let's calculate (200 V)^2:
(200 V)^2 = 40,000 V^2
Finally, we can substitute these values back into the equation:
E = (8.5 * 10^-6 F) * (40,000 V^2)
Now, let's calculate the result:
E = 340 * 10^-2 J
So, when the 17μF capacitor is charged to a potential difference of 200 V, the energy stored in it is 3.4 J (joules).
To calculate the energy stored in a capacitor, you can use the formula:
E = (1/2) * C * V^2
Where:
E is the energy stored in the capacitor
C is the capacitance of the capacitor
V is the potential difference (voltage) across the capacitor
In this case, the capacitance is given as 17μF (microfarads) and the potential difference is 200 V.
Substituting these values into the formula:
E = (1/2) * 17μF * (200V)^2
E = (1/2) * 17 * (10^-6) F * (200)^2 V^2
First, multiply 17 by (10^-6) to convert microfarads to farads:
E = (1/2) * 17 * (10^-6) F * (200)^2 V^2
E = (1/2) * 17 * (10^-6 F) * 40000 V^2
Now calculate the value of E:
E = (1/2) * 17 * (10^-6 F) * 40000 V^2
E = 0.034 joules
Therefore, the energy stored in the capacitor is 0.034 joules.