If sin a=0.31 cos a=0.95 sin b=0.47 and cos b=0.88 what is sin (a+b)?
0.78
-0.17
0.98
0.72
sin(a+b)=sinacosb+sinbcosa=.31*.88+.47*.95= I get about .72
do you have the rest of the answers?
To find the value of sin(a + b), we can use the trigonometric identity: sin(a + b) = sin(a)cos(b) + cos(a)sin(b).
Given:
sin(a) = 0.31
cos(a) = 0.95
sin(b) = 0.47
cos(b) = 0.88
Now, substitute the values into the identity:
sin(a + b) = sin(a)cos(b) + cos(a)sin(b)
sin(a + b) = (0.31)(0.88) + (0.95)(0.47)
sin(a + b) = 0.2728 + 0.4465
sin(a + b) = 0.7193
Therefore, sin(a + b) is approximately 0.7193.
To find the value of sin(a + b), we can use the trigonometric identity: sin(a + b) = sin(a)*cos(b) + cos(a)*sin(b).
Given that sin(a) = 0.31, cos(a) = 0.95, sin(b) = 0.47, and cos(b) = 0.88, we can substitute these values into the formula:
sin(a + b) = sin(a)*cos(b) + cos(a)*sin(b)
= (0.31)(0.88) + (0.95)(0.47)
= 0.2728 + 0.4465
= 0.7193
Therefore, sin(a + b) is approximately 0.7193.
Out of the options provided, the closest value to 0.7193 is 0.72.