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Physics

A thin copper rod 1m long has a mass of 50g. What should be the direction of magnetic field and the maximum current in the rod that would allow it to levitate above the ground in a magnetic field of 0.1T.

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  1. F = IBL
    F = mg

    mg = IBL

    I = mg / BL

    ( (0.05 kg)(9.8 m/s^2) / (0.1 T)(1 m) )

    = 4.9 A

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