Write a balanced equation for the dissolution
of sodium carbonate (Na2CO3) in water. Find
the number of moles of Na+ produced when
0.318 mol of sodium carbonate dissolves. Answer in units of mol.
The reaction is
Na2CO3 -> 2 Na+ + CO3(2-)
The balanced reaction equation tells you that each mole of sodium cardonate makes 2 moles of Na+.
So, double the 0.318
0.636
The balanced equation for the dissolution of sodium carbonate (Na2CO3) in water is as follows:
Na2CO3 (s) → 2 Na+ (aq) + CO3^2- (aq)
According to the balanced equation, 1 mole of sodium carbonate (Na2CO3) produces 2 moles of sodium ions (Na+). Therefore, if 0.318 mol of sodium carbonate dissolves, the number of moles of Na+ produced would be 2 times that amount.
Number of moles of Na+ = 2 × 0.318 mol
= 0.636 mol
Therefore, the number of moles of Na+ produced when 0.318 mol of sodium carbonate dissolves is 0.636 mol.
To write the balanced equation for the dissolution of sodium carbonate (Na2CO3) in water, we need to know that sodium carbonate dissociates in water to form sodium ions (Na+) and carbonate ions (CO3^2-).
The balanced equation can be written as follows:
Na2CO3 (s) → 2 Na+ (aq) + CO3^2- (aq)
Now, to find the number of moles of Na+ produced when 0.318 mol of sodium carbonate dissolves, we need to use stoichiometry. Looking at the balanced equation, we can see that 1 mole of sodium carbonate produces 2 moles of Na+.
Therefore, to find the number of moles of Na+ produced, we can use the following calculation:
Number of moles of Na+ = 2 × Number of moles of sodium carbonate
Plugging in the given value, we have:
Number of moles of Na+ = 2 × 0.318 mol = 0.636 mol
Therefore, the number of moles of Na+ produced when 0.318 mol of sodium carbonate dissolves is 0.636 mol.