What are the first four terms in this sequence represented by the expression n(n-2)-3?
It's B
B. -4,-3,0,5
term(n) = n(n-2)-3
term(1) = 1(1-2) - 3 = 1(-1) - 3 = -4
term(2) = 2(2-2) - 3 = 2(0) - 3 = -3
continue
This seems like a good answer anybody have the full test answers?
A. -5,-2,1,4
B. -4,-3,0,5
C. -3,0,3,6
D.-2,0,2,6
These are my answers, but how do I find it. When I tried reiny's way, I got -4,-3,-2,-1, and 0.......... So how do I find the correct answer????? Whatever I'll figure it out hopefully I don't fail my test because of these stupid questions........ PEACE!!!!
no he was right
What are the first 3 terms of the sequence represented by the expression n(n – 2) – 4 ?
To find the first three terms of the sequence, we need to substitute n = 1, 2, and 3 into the expression and simplify:
When n = 1:
term(1) = 1(1 - 2) - 4 = -5
When n = 2:
term(2) = 2(2 - 2) - 4 = -4
When n = 3:
term(3) = 3(3 - 2) - 4 = -1
Therefore, the first 3 terms of the sequence are -5, -4, and -1.
All I know is that
#1 is 38, 49, 60
#2 is 2,048
and
#3 is -4,-3, 0, 5