To solve the equation sin(a) = 2, we first need to clarify the range of solutions. The function sin(a) oscillates between -1 and 1, so we know that there are no solutions for a when sin(a) exceeds these limits. In this case, sin(a) = 2 is outside the range of the sine function, so there are no solutions to the equation within the given range of 0 < a < 2π.