A guy rope is attached to the top of a tent pole. The guy rope is pegged into the ground 7 feet from the tent. If the guy rope is 11 feet long, how long is the tent pole? Round to one decimal place as needed.
HELP whats the answer
To find the length of the tent pole, we can use the Pythagorean Theorem because the guy rope and the tent pole form a right triangle.
Let's call the length of the tent pole "x".
According to the Pythagorean Theorem, the sum of the squares of the lengths of the two legs of a right triangle is equal to the square of the length of the hypotenuse.
So, we can set up the equation:
x^2 = 11^2 - 7^2
Simplifying this equation:
x^2 = 121 - 49
x^2 = 72
To solve for x, we take the square root of both sides:
x = √72
Calculating the square root:
x ≈ 8.5
Therefore, the length of the tent pole is approximately 8.5 feet.
To find the length of the tent pole, we can use the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In this case, the guy rope, which is the hypotenuse, has a length of 11 feet. The distance from the tent to the peg in the ground is the other side of the triangle and has a length of 7 feet. Let's call the length of the tent pole "x".
Applying the Pythagorean theorem, we have:
x² = 11² - 7²
x² = 121 - 49
x² = 72
To solve for x, we take the square root of both sides:
x = √72
Using a calculator, we find that √72 is approximately 8.49. Therefore, the length of the tent pole is approximately 8.5 feet, rounded to one decimal place.
what the heck -- post it again, and maybe this time you'll spell "algebra" correctly.
Just sayin'