In a titration experiment, 15.0 mL of 0.10 M Ba(OH)2 is required to titrate a 10.0 mL of an unknown solution of HNO3. Calculate the concentration of the HNO3
solution using the data. 2HNO3 + Ba(OH)2 ® Ba(NO3)2 + 2H2O
2HNO3 + Ba(OH)2 ==> 2H2O + Ba(NO3)2
mols Ba(OH)2 = M x L = ?
From the equation, you know mols HNO3 = twice moles Ba(OH)2
Then M HNO3 = mols HNO3/L HNo3
To calculate the concentration of the HNO3 solution, we can use the stoichiometry of the reaction and the volume of the known Ba(OH)2 solution used in the titration.
Let's break down the steps to find the concentration of HNO3:
Step 1: Write the balanced chemical equation for the reaction:
2HNO3 + Ba(OH)2 -> Ba(NO3)2 + 2H2O
Step 2: Determine the moles of Ba(OH)2 used:
Using the concentration and volume of Ba(OH)2 used in the titration, we can calculate the moles of Ba(OH)2:
Moles of Ba(OH)2 = concentration of Ba(OH)2 × volume of Ba(OH)2 used
Moles of Ba(OH)2 = 0.10 M × 15.0 mL
Step 3: Determine the moles of HNO3 reacted:
Since the stoichiometry of the reaction is 2:1 for HNO3 to Ba(OH)2, the moles of HNO3 will be half the moles of Ba(OH)2:
Moles of HNO3 = (0.10 M × 15.0 mL) / 2
Step 4: Calculate the concentration of HNO3:
The concentration of HNO3 can be found by dividing the moles of HNO3 by the volume of the HNO3 solution used:
Concentration of HNO3 = Moles of HNO3 / Volume of HNO3 used
Concentration of HNO3 = (0.10 M × 15.0 mL) / (10.0 mL)
Now, let's calculate the concentration of HNO3:
Concentration of HNO3 = (0.10 M × 15.0 mL) / (10.0 mL)
Concentration of HNO3 = 0.15 M
Therefore, the concentration of the HNO3 solution is 0.15 M.