2 Questions.
1. If you wished to produce a sound with a wavelenght in air equal to the length of the room, 10m, what would be its frequency?
2.You note a 4.0 second delay for an echo in a canyon. What is the distance to the wall of the canyon?
1. Use the same formula as in your radiop wave qudestion, except this time you use the sounds speed.
(frequency = (sound speed)/(wavelength)
2. (Sound delay)x(speed of sound =
2 x distance to the wall.
Solve for the distance.
1. To determine the frequency of a sound wave with a wavelength equal to the length of the room, we can use the formula:
Frequency = Speed of Sound / Wavelength
In this case, the wavelength is given as 10 meters. The speed of sound in air is approximately 343 meters per second. Plugging these values into the formula, we get:
Frequency = 343 m/s / 10 m
Frequency = 34.3 Hz
Therefore, the frequency of the sound wave would be approximately 34.3 Hz.
2. To calculate the distance to the wall of the canyon based on the echo delay, we can utilize the relationship between speed, time, and distance:
Distance = (Speed of Sound x Time) / 2
In this case, the echo delay is given as 4.0 seconds. The speed of sound in air is still approximately 343 meters per second. Plugging these values into the formula, we have:
Distance = (343 m/s x 4.0 s) / 2
Distance = 686 m
Therefore, the distance to the wall of the canyon would be approximately 686 meters.