How do I find the slope of the line through (-9, -10) and (-2,-5)?
the slope is, as always, ∆y/∆x = (-5-(-10))/(-2-(-9)) = 5/7
for two points, (x1,y1) and (x2,y2)
the slope = (y2-y1)/(x2-x1)
apply it to your two points, show me your work
To find the slope of a line given two points, you can use the formula:
slope = (change in y-coordinates)/(change in x-coordinates)
In this case, the two points are (-9, -10) and (-2, -5).
Step 1: Determine the change in y-coordinates:
To find the change in y-coordinates, subtract the y-coordinate of the first point from the y-coordinate of the second point:
change in y = -5 - (-10) = -5 + 10 = 5
Step 2: Determine the change in x-coordinates:
To find the change in x-coordinates, subtract the x-coordinate of the first point from the x-coordinate of the second point:
change in x = -2 - (-9) = -2 + 9 = 7
Step 3: Calculate the slope:
Plug the values of change in y and change in x into the formula for the slope:
slope = (5)/(7)
Therefore, the slope of the line passing through the points (-9, -10) and (-2, -5) is 5/7.