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Given that Sinharch(x)=ln(x+√x^2+1),determine Sinharch(2+j) in the form a+bj

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asked by joek
  1. √((2+j)^2+1)=2√(1+j) = 1.197+0.910j
    so you want
    log(3.197+1.910j)
    Now recall that if z=a+bj then log(z) = log|z|+arccos(a/|z|)j

    posted by Steve

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