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Trig Help
Prove the following: [1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)] =[sinx+sin^2x]/[sinx+1] =[sinx+(1cos^2x)]/[sinx+1] =??? This is where I'm stuck. Can someone help me.
asked by Anonymous on March 11, 2012 
Trig........
I need to prove that the following is true. Thanks (cosx / 1sinx ) = ( 1+sinx / cosx ) I recall this question causing all kinds of problems when I was still teaching. it requires a little "trick" L.S. =cosx/(1sinx) multiply top
asked by abdo on April 18, 2007 
math
the problem is 2cos^2x + sinx1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is what i've done so far: 2cos^2x+sinx1=0 2cos^2x1+sinx=0 cos2x + sinx =0 1  2sin^2x + sinx = 0
asked by alex on April 7, 2008 
Trigonometry.
( tanx/1cotx )+ (cotx/1tanx)= (1+secxcscx) Good one! Generally these are done by changing everything to sines and cosines, unless you see some obvious identities. Also generally, it is best to start with the more complicated
asked by mo on April 18, 2007 
trigonometry
can i use factoring to simplify this trig identity? the problem is sinx + cotx * cosx i know the answer is cscx and i know how to get it but i want to know if i can do factoring to get it bc i tried to but it wont give me the
asked by v on December 3, 2012 
Simplifying with Trigonometry Identities
Hi, I am a senior in High School having a really difficult time with two problems. I have to prove using the trigonometric identities that they equal each other but I am having a really hard time trying to get them to equal each
asked by amanda on March 7, 2007 
Precalc
prove the identity: (cosx)(tanx + sinx cotx)=sinx+cos(squared)x i need steps to show how i got the answer generally, it is a good idea to change all trig ratios to sines and cosines, and start with the more complicatedlooking
asked by Stacey on May 6, 2007 
Math Help
Hello! Can someone please check and see if I did this right? Thanks! :) Directions: Find the exact solutions of the equation in the interval [0,2pi] cos2x+sinx=0 My answer: cos2x+sinx=cos^2xsin^2x+sinx =1sin^2xsin^2x+sinx
asked by Maggie on February 2, 2015 
maths  trigonometry
I've asked about this same question before, and someone gave me the way to finish, which I understand to some extent. I need help figuring out what they did in the second step though. How they got to the third step from the
asked by anonymous on June 19, 2010 
Math
1) evaluate without a calculator: a)sin(3.14/4) b) cos(3(3.14)/4) c) tan(4(3.14)/3) d) arccos( square root of three/2) e) csctheata=2 2) verify the following identities: a) cotxcosx+sinx=cscx b)[(1+sinx)/ cosx] + [cosx/
asked by Emily on August 22, 2013 
PreCalc : Verify the Identity
Verify the Identity: sin(x+π)/cos(x+3π/2) =tan^2xsec^2x I've done: sinxcosπ+cosxsinπ / cosxcos(3π/2)  sinxsin(3π/2) sinx(1) + cosx(0) / cosx(0) sinx(1) sinx/sinx What do I do from here? Or what did I do wrong?
asked by Phil HELP NEEDED ASAP on May 10, 2013