algebra

The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right.
Find the GCF:
16x^2z ,40xz^2 , 72z^3
= 3^3z

Factor our GCF:
a(a+1) - 3(a+1)
= a+1

Factor Polynomial:
9a^2 - 64b^2
= (3a+8b)(3a-8b)

9w - w^3
= w(3) (?really unsure if correct?)

I'm not sure how to do the following, or where to even begin. Some help getting started would be very appreciated! :)

Factor Polynomials:
x^3y + 2x^2y^2 + xy^3

x^3 + ax + 3a + 3x^2

Factor:
18z + 45 +z^2

  1. 👍 0
  2. 👎 0
  3. 👁 179
  1. 16x^2z ,40xz^2 , 72z^3
    the GCF I see is 4xz, I can't see how you got your answer.

    a(a+1) - 3(a+1)
    = (a+1)(a-3) fully factored

    9a^2 - 64b^2
    = (3a+8b)(3a-8b) that is ok

    9w - w^3 , I see a common factor of 3w
    = 3w(3 - w^2)

    x^3y + 2x^2y^2 + xy^3 first go for a common factor
    = xy(x^2 + 2xy + y^2)
    = xy(x+y)(x+y)
    = xy(x+y)^2

    x^3 + ax + 3a + 3x^2
    this is a "grouping" type of factoring
    = x^3 + 3x^2 + ax + 3a
    = x^2(x+3) + a(x+3)
    = (x+3)(a+3)

    18z + 45 +z^2
    = z^2 + 18z + 45
    = (z+15)(z+3)

    1. 👍 0
    2. 👎 0
    posted by Reiny
  2. in the first one: 16x^2z ,40xz^2 , 72z^3
    the only question I have is, how can it be 4xz when they don't all have the variable 'x'? the way I factored it was like this:
    16x^2z
    16 = 8 & 2 x^2z
    4&2 (x)(x)(z)
    2&2
    = 2^4

    40xz^2
    40 = 10 & 4 xz^2
    5&2 2&2 (x)(z)(z)
    = 5(2^3)

    72z^3
    72 = 36 & 2 z^3
    18&2 (z)(z)(z)
    9&2
    3&3
    = 3^2(2^3)

    with the answer being 2^3z, which is what they all have in common

    1. 👍 0
    2. 👎 0
    posted by kay bri
  3. 3w-3

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Algebra

    The first three equations I have solved, I would just appreciate someone checking them over to make sure I'm doing them right. Find the GCF: 16x^2z ,40xz^2 , 72z^3 = 3^3z Factor our GCF: a(a+1) - 3(a+1) = a+1 Factor Polynomial:

    asked by KB on January 22, 2009
  2. algebra 2

    Solve the following systems of equations. If the system cannot be solved ,state that it cannot be solved and explain why. 1.3x+y=7 3x+y=10 2. 5x-2y=-24 -4y=-48-10x

    asked by Hannah on September 24, 2014
  3. Math..

    4(x+1/2)-2(x+3/2) less than. Or equal to 5 ( i. Solved it im just checking my answers to be sure )

    asked by Jim on March 17, 2013
  4. Vectors - Reiny

    Thank you for the help! "When I solved equations 2 and 3 I got u=0 and t=-1, giving me r = (-2,-3,0) in both r = ... equations." Ok I'll check that. I just have a question...how would you get r = (-2,-3,0) when u = 0 and t = -1?

    asked by Alex on April 7, 2008
  5. Math

    Can you Check my work please? Let N(t) be the number of bacteria after t days. Then N(t) = Pa^t for some constants P and a. Measurements indicate that N(4) = 5600 and N(8) = 362, 000. b. Write down two equations for P and a, one

    asked by Walt on February 13, 2012
  6. Algebra

    Find all solutions to the following system of equations: x + 3y + 2z = 6 -3x + y + 5z = 29 -2x - 3y + z = 14 This just did not work out for me. Here is my work: I first solved Equation #1 for x. x = -3y - 2z + 6 Then, I did

    asked by Anneliese on February 25, 2009
  7. Physics

    With your equations, I solved for the two unknown variables and got the correct answers for the forces. Thanks! Unfortunately, I don't really understand how you came up with those two equations in the first place. I set up a

    asked by Jessica on March 10, 2008
  8. math

    pls help me to solved this equation 1. 6y=x+18 2y-x=6, 2. 4x=3y=13 2x-4y=1 3. y=3x-12 2/3x=2/3-1/6y pls help me now. this equation is Systems of Linear Equations Solved Algebraically.

    asked by joy on July 25, 2010
  9. Algebra

    1. The length of a rectangle is twice its width. The perimeter of the rectangle is 24 inches. Write a system of equations in 2 variables. Use substitution to solve the problem. A. Equation 1: L = 2W L= 2(4) = 8 Equation 2: 2L + 2W

    asked by X on June 4, 2017
  10. Basic Math

    I forgot how to solve for two variables... Please check if I solved both problems properly! Thank you. Equations: (solve for t and z) 12t + 4z = 80 2t + 4z = 20 My answer: t = 2, z = 14 The steps: (simplified it) z = 20 - 3t, z =

    asked by Anonymous on January 10, 2009

More Similar Questions