0.5 mol CCl4 is introduced into a 10.0L flask .what fraction of the total volume of flask is occupied by CCl4 molecules?
all of it if it's a gas.
If a liquid, then you need to look up the density of CCl4 (convert to g/L)
find how many grams is .5 mol
volume = mass/density
divide that by 10.0L
To find the fraction of the total volume of the flask occupied by CCl4 molecules, we need to know the molar volume of CCl4.
The molar volume is defined as the volume occupied by one mole of any substance at a given temperature and pressure. It can be calculated by dividing the molar mass of the substance by its density.
The molar mass of CCl4 can be calculated by adding up the atomic masses of its constituent elements: Carbon (C) has a molar mass of 12.01 g/mol, and each Chlorine atom (Cl) has a molar mass of 35.45 g/mol. Since CCl4 has four chlorine atoms, its molar mass is:
Molar mass of CCl4 = (12.01 g/mol) + 4 * (35.45 g/mol) = 153.82 g/mol
The density of CCl4 is 1.586 g/mL, which means that one milliliter of CCl4 has a mass of 1.586 grams.
Now we can calculate the molar volume of CCl4 by dividing the molar mass by the density:
Molar volume of CCl4 = Molar mass / Density = (153.82 g/mol) / (1.586 g/mL) = 96.89 mL/mol
So, 1 mole of CCl4 occupies a volume of 96.89 mL.
Since you have 0.5 moles of CCl4, you can calculate the volume it occupies by multiplying the molar volume by the number of moles:
Volume occupied by 0.5 moles of CCl4 = 0.5 moles * (96.89 mL/mol) = 48.45 mL
However, the flask volume is given in liters (L), so we need to convert the volume to liters:
Volume occupied by 0.5 moles of CCl4 = 48.45 mL * (1 L / 1000 mL) = 0.04845 L
To find the fraction of the total volume, divide the volume occupied by CCl4 by the total volume of the flask:
Fraction = Volume occupied by CCl4 / Total volume of flask = 0.04845 L / 10.0 L = 0.004845 or 0.4845%
Therefore, 0.4845% of the total volume of the flask is occupied by CCl4 molecules.