A construction company uses a crane to lift a wrecking ball2000kg the crane can cause the wrecking ball to speed up from rest to 0.1m/s in 0.2 second what is the acceleration of the wrecking ball during this time
a = dv/dt = (0.1 - 0)/0.2 = 0.5 m/s^2
V = Vo + a*t = 0.1
0 + a * 0.2 = 0.1,
a = 0.5 m/s^2.
To find the acceleration of the wrecking ball during the given time, we can use the formula for acceleration:
Acceleration (a) = (Final Velocity (v) - Initial Velocity (u)) / Time (t)
Here, the initial velocity (u) is 0 m/s (because the wrecking ball is at rest), the final velocity (v) is 0.1 m/s, and the time (t) is 0.2 seconds.
Plugging in the values into the formula, we get:
Acceleration (a) = (0.1 m/s - 0 m/s) / 0.2 s
Simplifying the equation, we have:
Acceleration (a) = 0.1 m/s / 0.2 s
Dividing 0.1 m/s by 0.2 s, we find:
Acceleration (a) = 0.5 m/s²
Therefore, the acceleration of the wrecking ball during this time is 0.5 m/s².