copper(II) nitrate and barium sulfide
Express your answer as a complete ionic equation and a net ionic equation.
Barium Sulfide is BaS
You are absolutely right.
BaSO4 is barium sulfate. BaS is barium sulfide and I misread the question.BaS is soluble and a reaction will take place.
Cu(NO3)2 + BaS ==> Ba(NO3)2 + CuS
You can turn that into an ionic equation.
The net equation is
Cu^2+(aq) + S^2-(aq) ==> CuS(s)
Thank You!
To determine the complete ionic equation and net ionic equation for the reaction between copper(II) nitrate (Cu(NO3)2) and barium sulfide (BaS), we first need to identify the ions present in each compound.
Copper(II) nitrate dissociates into copper(II) ions (Cu2+) and nitrate ions (NO3-). Barium sulfide dissociates into barium ions (Ba2+) and sulfide ions (S2-).
The balanced chemical equation for this reaction is:
Cu(NO3)2 + BaS → CuS + Ba(NO3)2
To write the complete ionic equation, we need to represent all the ions that are present in their respective aqueous solutions:
Cu2+(aq) + 2NO3-(aq) + Ba2+(aq) + S2-(aq) → CuS(s) + Ba2+(aq) + 2NO3-(aq)
In the complete ionic equation, the ions that are aqueous (soluble) are split into their individual ions.
To write the net ionic equation, we need to eliminate the spectator ions, which are ions that are present on both sides of the equation and do not participate in the reaction.
In this case, the spectator ions are Ba2+ and NO3-.
The net ionic equation is:
Cu2+(aq) + S2-(aq) → CuS(s)
In the net ionic equation, only the ions that are directly involved in the reaction are shown.
Therefore, the complete ionic equation for the reaction between copper(II) nitrate and barium sulfide is:
Cu2+(aq) + 2NO3-(aq) + Ba2+(aq) + S2-(aq) → CuS(s) + Ba2+(aq) + 2NO3-(aq)
And the net ionic equation is:
Cu2+(aq) + S2-(aq) → CuS(s)