a village is 10km on a bearing of 050 degree 4rm a point 0.how far is d village north of 0?
Cos 50=x/10
0.6428/1=X/1
X=6.428
X=6.4
Agreeing with bobpursley and
trying to make sense of your atrocious spelling, 4rm ----> from ??, d ----> the ????
you probably want:
y/10 = cos50
y = 10cos50 = ....
Cos 50°= opp/adj
Cos 50°= x/10
0.6428/1= y/10
y= 10x0.6428
y= 6.428
50/cos/10= 6428
To find the distance that the village is north of point 0, we can use trigonometry. Here's how you can do it:
Step 1: Draw a diagram representing the given information. Place point 0 at the origin and draw a line representing the bearing of 050 degrees. Mark the village on this line, which is 10 km away from point 0.
Step 2: Since we want to find how far the village is north of point 0, we need to determine the "north" component of the 10 km distance. To do this, we need to find the "adjacent" side of the right triangle formed by the line and the north axis.
Step 3: In the right triangle, the hypotenuse is the 10 km distance, the angle is 050 degrees, and we want to find the adjacent side. We can use trigonometric ratios to solve for the adjacent side. In this case, we need to use the cosine function.
Step 4: The cosine function is defined as the ratio of the adjacent side length to the hypotenuse length. So, we have:
cos(angle) = adjacent / hypotenuse
Substituting the given values, we have:
cos(50 degrees) = adjacent / 10 km
Now, solve for the adjacent side (which represents the northward distance):
adjacent = cos(50 degrees) * 10 km
Using a calculator, the value of cos(50 degrees) is approximately 0.6428. Therefore:
adjacent = 0.6428 * 10 km
adjacent = 6.428 km
So, the village is approximately 6.428 km north of point 0.
Hmmmm. Bearings should be from N, clockwise, so 050 is E of N, going S.
So I dont understand your coordinate system