During a titration experiment, a 130.0 mL solution of 0.02 M hydrogen chloride (HCl) is neutralized by 100.0 mL of unknown concentration of lithium hydroxide (LiOH).

In this experiment, how many moles of lithium hydroxide are used?

0.024, correct?

I think you punched in the wrong numbers; i.e., hit a wrong key.

mols LiOH = mols HCl = M HCl x L HCl = ?

0.026?

I don't think 0.130 x 0.02 = 0.026 either.

I’m confused. I multiplied 0.130 by 0.02 and got 0.0026. However, the only options I have are:

0.024
0.066
0.026
0.260

0.0026 is the correct answer. Check the problem to make sure you typed it in correctly. If the problem is typed in correctly then the prof didn't give the correct answer as one of the choices.

To determine the number of moles of lithium hydroxide (LiOH) used in the titration experiment, we need to use the concept of stoichiometry and the relationship between moles, concentration, and volume.

In this case, we know the initial volume and concentration of the hydrogen chloride (HCl) solution and the volume of the lithium hydroxide (LiOH) solution used. However, we do not know the concentration of the LiOH solution.

To calculate the number of moles of LiOH, we first need to identify the limiting reactant. The limiting reactant is the substance that is completely consumed during the reaction and determines the maximum amount of product that can be formed.

To find the limiting reactant, we can compare the number of moles of HCl and LiOH using the following balanced chemical equation:

HCl + LiOH -> H2O + LiCl

From the equation, we can see that the mole ratio between HCl and LiOH is 1:1. Therefore, the number of moles of LiOH used will be equal to the number of moles of HCl used.

Given that the initial volume of the HCl solution is 130.0 mL and the concentration is 0.02 M, we can calculate the number of moles of HCl:

moles of HCl = volume of HCl solution (L) * concentration of HCl (mol/L)

Converting the volume from milliliters (mL) to liters (L):

volume of HCl solution = 130.0 mL * (1 L / 1000 mL) = 0.130 L

Now, calculate the number of moles of HCl:

moles of HCl = 0.130 L * 0.02 mol/L = 0.0026 mol

Since the mole ratio between HCl and LiOH is 1:1, the number of moles of LiOH used is also 0.0026 mol.

Therefore, the correct answer is 0.0026 moles of LiOH, not 0.024 moles as you suggested.