If 44.25 kJ of heat are released by changing 150. g of liquid mercury to mercury vapor,
what is the latent heat of vaporization for mercury in kJ/kg?
29,500 kJ/kg
0.3 kJ/kg
295 kJ/kg
3.4 kJ/kg
I believe the answer is 295 but I am not sure
44.25 kJ /0.150kg = ???
To find the latent heat of vaporization for mercury in kJ/kg, we first need to determine the amount of heat released per kilogram of mercury.
Given:
Heat released = 44.25 kJ
Mass of liquid mercury = 150 g = 0.15 kg
To calculate the latent heat of vaporization, we divide the heat released by the mass of substance involved:
Latent heat of vaporization = Heat released / Mass of substance
Latent heat of vaporization = 44.25 kJ / 0.15 kg
Calculating this, we get:
Latent heat of vaporization = 295 kJ/kg
Therefore, the latent heat of vaporization for mercury is 295 kJ/kg. Your answer is correct.