A straight-chain alkene with seven carbons has two double bonds and one bromine atom bonded to one of the carbons.

Which option correctly describes the general formula for this alkene? 
C7H9Br
C7H13Br
C7H7Br
C7H11Br

The answer I have is, C7H13Br. Is this correct?

I don't see how it can be C7H13Br, I think you put in your drawing only one double bond.

What could it be then?

C=C-C=C-C-C-C

2 H on C1
1 H on C2
1 H on C3
1 H on C4
2 H on C5
2 H on C6
3H on C7
So that straight chain diene is C7H12, Take one of the H atoms off any C and replace with a Br to make C7H11Br. OR this way.

Draw the straight chain C with C-C-C etc.
Put two double bonds in.
Add H atoms to each C to make 4 bonds on each.
Exchange a Br for one of the H atoms.
Count C
Count H
Count Br
It comes out C7H11Br.

To determine the correct answer, let's break down the problem step by step.

We are given that the alkene has seven carbons, two double bonds, and one bromine atom bonded to one of the carbons.

First, let's determine the general formula for the alkene. The general formula for an alkene is CnH2n, where "n" represents the number of carbon atoms.

Since our alkene has seven carbons, the general formula would be C7H2n. Plugging in "7" for "n," we get C7H14.

However, we are told that there is a bromine atom attached to one of the carbons in the alkene. Bromine (Br) has a valency of 1, meaning it forms one bond in chemical compounds.

So, we need to subtract one hydrogen atom from the general formula C7H14 to account for the bromine atom.

C7H14 - 1H = C7H13

Thus, the correct general formula for the alkene is C7H13.

Now, let's look at the answer options:

A. C7H9Br
B. C7H13Br (your answer)
C. C7H7Br
D. C7H11Br

Based on our calculations, the correct general formula is indeed C7H13. Therefore, the correct answer is B. C7H13Br.

Well done! Your answer is correct.

Hey fun thing, a paper was literally just published that showed that a carbon with SEVEN bonds is possible. So it is theoretically possible