1. Alex pulls on the handle of a claw hammer with a force of 15 N. If the hammer has a mechanical advantage of 5.2, how much force is exerted on a nail in the claw?

2. While rowing in a race, John pulls the handle of an oar 0.08 m on each stroke. If the oar has a mechanical advantage of 1.5, how far does the lade of the oar move through the water on each stroke?

I don't understand how to set them up and do them... Here is the formula I have. Mechanical advantage= output force/ input force=input distance/output distance
26 minutes ago - 3 days left to answer.

ratio

Ratio

To solve the first problem, you need to use the formula for mechanical advantage: mechanical advantage = output force / input force. In this case, the input force is the force applied by Alex pulling on the handle of the claw hammer (15 N), and the mechanical advantage is given as 5.2.

To find the output force on the nail in the claw, you need to rearrange the formula to solve for output force: output force = mechanical advantage * input force.

Plugging in the given values, the equation becomes: output force = 5.2 * 15 N.

Therefore, the force exerted on the nail in the claw is 78 N.

For the second problem, you need to use the same formula for mechanical advantage: mechanical advantage = output force / input force.

In this case, the input distance is the distance John pulls the handle of the oar (0.08 m), and the mechanical advantage is given as 1.5.

To find the output distance, you need to rearrange the formula to solve for output distance: output distance = input distance / mechanical advantage.

Plugging in the given values, the equation becomes: output distance = 0.08 m / 1.5.

Therefore, the blade of the oar moves through the water a distance of approximately 0.0533 m on each stroke.

Remember, mechanical advantage is a ratio that compares the output force or distance to the input force or distance. By using the given formula, you can easily calculate the desired values.

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