While traveling in Egypt, Judah carefully peeked into his wallet and found that he had $80 in $10 and $5 bills. If there were 4 fewer $10 bills thn $5 bills, how many of each did Judah have?
I tried this problem over and over and it just isnt clicking in my brain... can u pls help me find then answer? it would mean a lot to me
ty, God Bless you all
value equation: T*10+F*5=80 where t, F are numbers of bills
number of bills: T+4=F put this in the first equation.
10T+5(T+4)=80
solve for T, then put that into F=T+4
Of course, I'd be happy to help you solve this problem!
Let's break down the information that we have:
1. Judah has $80 in $10 and $5 bills.
2. There are 4 fewer $10 bills than $5 bills.
To solve this problem, we can set up a system of equations based on the information given.
Let's assume that the number of $10 bills is represented by 'x', and the number of $5 bills is represented by 'y'.
Now let's write the equations:
1. The total value of $10 bills is 10x.
2. The total value of $5 bills is 5y.
3. The total value of all the bills is given as $80, so we can write the equation: 10x + 5y = 80.
We are also given that there are 4 fewer $10 bills than $5 bills. This can be represented as: x = y - 4.
Now we have a system of two equations:
Equation 1: 10x + 5y = 80
Equation 2: x = y - 4
To solve this system, we can substitute equation 2 into equation 1:
10(y - 4) + 5y = 80
10y - 40 + 5y = 80
15y - 40 = 80
15y = 120
y = 8
Now, substitute the value of y back into equation 2 to find x:
x = 8 - 4
x = 4
So Judah has 4 $10 bills and 8 $5 bills.
I hope this explanation helps you understand how to solve the problem! If you have any further questions, please let me know.