1/x+12=3x/3x^2+36

If you typed the equation correctly, this is the way I interpret it.

1/x + 12 = 3x/3x^2 + 36

On the right side, the 3x terms cancel each other out.

1/x + 12 = 1/x + 36

To get x out of denominator, multiply both sides by x.

1 + 12x = 1 + 36x

Get like terms on the same side of the equation by subtracting 1 and 12x from both sides.

0 = 24x

x = 0

However, this does not check out when you substitute that value into the equation. I see no solution to this equation as you have typed it.

I hope this helps. Thanks for asking.