Physics

An object is placed at a distance of 60 cm from a converging lens with a focal length of 20cm. What is the magnification of the lens?

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  1. (I shall use the Cartesian Sign Convention)

    Object distance = u = - 60cm
    Focal length = f = + 20cm (The focal length of a converging lens is taken as positive)

    Image distance = v

    As per the lens formula,
    (1/v) = (1/u) + (1/f)
    (1/v) = (1/20) - (1/60)
    v = 30 cm

    Magnification = -(v/u)
    = 30/60
    = 0.5

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  2. Why do object distance consider as negative

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