A stationary 14 kg shell explodes into two pieces. If the 5 kg piece has a velocity of -70 m/s, determine the velocity of the other piece. Do not round your answer until the end!
i got 38.89
According to law of conservation of momentum-
Momentum before explosion=momentum after explosion
mv=m1v1+m2v2
14×0=5×-70+9×v2
0=-350+9v2
350=9v2
v2=350÷9
v2=38.89 m/s