You randomly draw marbles from a bag containing both blue and green marbles, without replacing the marbles between draws. If B=drawing a blue marble and G=drawing a green marble, which represents the probability of drawing a blue marble first and a green marble second?
A. P(B)⋅P(G)
B. P(B and G)
C. P(G after B)
D. P(B, then G)
Suppose a bag contains 3 blue and 2 green marbles. You randomly draw 2 marbles without replacement. If B=drawing a blue marble and G=drawing a green marble, which event does NOT have the same probability as the others?
Bag
A. GG
B. BB
C. GB
D. BG
yhngrbfeds
To determine the probability of drawing a blue marble first and a green marble second, we need to compute the probability of each event happening independently and then multiply them together.
Let's break this down:
P(B) represents the probability of drawing a blue marble first. To calculate this probability, we need to know the number of blue marbles and the total number of marbles in the bag.
P(G) represents the probability of drawing a green marble second. Since we have already drawn a blue marble and not replaced it, the number of marbles in the bag has changed. We now need to consider the number of green marbles and the remaining total number of marbles in the bag.
Now, the probability of drawing a blue marble first and then a green marble is the product of P(B) and P(G). Therefore, the correct answer is A. P(B)⋅P(G).
You are not replacing, so A is hopelessly out
The probability of drawing a green CHANGES after your first draw if you do not replace.
Only one choice is specific about drawing blue first and green second.