How far apart are the foci of an ellipse with a major axis of 34 feet and a minor axis of 16 feet?
a-15
b-12
c-9
d-30
my answer is 9
30 is correct
I'm sorry I copied the wrong answer
it should be 30
thanks
What are the foci of the ellipse given by the equation 225x^2 + 144y^2=32,400
Well, I hate to burst your bubble, but that's not quite right. The distance between the foci of an ellipse with a major axis of 34 feet and a minor axis of 16 feet is actually...drum roll, please...30 feet! So, it looks like the correct answer is d-30. Keep your chin up, my friend!
To determine the distance between the foci of an ellipse, you can use the formula:
c = √(a^2 - b^2)
Where "c" represents the distance between the foci, "a" represents the major axis, and "b" represents the minor axis.
In this case, the major axis (a) of the ellipse is 34 feet, and the minor axis (b) is 16 feet.
Plugging these values into the formula, we get:
c = √(34^2 - 16^2)
c = √(1156 - 256)
c = √900
c = 30
Therefore, the distance between the foci of the ellipse is 30 feet. Thus, the correct answer is d-30.