1.How much heat is absorbed by a 63g iron skillet when its temperature rises from 12oC to 30oC?
2.How much heat is needed to raise the temperature of 5g of water by 15oC?
heat capacity of Fe * 63 * (30-12)
And for the second one?
same job
specific heat of water * 5 * 15
you need specific heat in Joules/g deg C or Cal/g deg C
I do not know what your class is using
To calculate the amount of heat absorbed by an object when its temperature changes, you can use the formula:
Q = m * C * ΔT
Where:
Q is the heat absorbed or released (in Joules)
m is the mass of the object (in grams)
C is the specific heat capacity of the substance (in J/g°C)
ΔT is the change in temperature (in °C)
1. For the first question, you have a 63g iron skillet, and the temperature change is from 12°C to 30°C.
First, you need to find the specific heat capacity of iron. The specific heat capacity of iron is approximately 0.45 J/g°C.
Now, plug in the values into the formula:
Q = 63g * 0.45 J/g°C * (30°C - 12°C)
Q = 63g * 0.45 J/g°C * 18°C
Q = 510.3 Joules
Therefore, the amount of heat absorbed by the 63g iron skillet is 510.3 Joules.
2. For the second question, you have 5g of water, and the temperature change is 15°C.
The specific heat capacity of water is approximately 4.18 J/g°C.
Now, use the formula:
Q = 5g * 4.18 J/g°C * 15°C
Q = 313.5 Joules
Therefore, the amount of heat needed to raise the temperature of 5g of water by 15°C is 313.5 Joules.