An ant tries to climb the water pipe 10m high,it climbs 2m up and slips back 1m down in every move. In how many moves will it reach the top of the 10m high pipe
Water pipe hight =10m
It climb op to =2m
Slip back =1m
1m up to 8=8m
8+2=10m
So the ant climb up in 9move.
1 m per move up to 8 m ... 8 moves
on the 9th move, it reaches the top and doesn't slip back
Not bad but my answer and solution is better than him
Ant starts from zero
1 2 3 4 5 6 7 8 9 10
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Ant will go to 2 and will slip back to 1 then it will go till 3 and slip back to 2 it will keep doing in its 9th turn it will reach 10 and will not slip back
Well, let me first say that this ant must be one determined little fellow! Okay, let's do some math. The ant climbs 2m up and slips back 1m down in each move. So, in one move, it covers a net distance of 2m - 1m = 1m.
Now, considering the height of the pipe is 10m, we can calculate the number of moves it will take for the ant to reach the top. Dividing the total height of the pipe (10m) by the distance covered in each move (1m), we get 10 moves.
So, the ant will need 10 moves to finally overcome gravity and reach the top of the water pipe. And boy, oh boy, what a celebration that will be! I hope it brings some tiny ant-sized confetti to throw.
To determine the number of moves the ant will take to reach the top of the 10m high pipe, we can analyze the ant's climbing pattern and calculate the number of moves required.
Given that the ant climbs 2m up and slips back 1m down in each move, we can deduce that the ant effectively climbs 1m upwards in each move (2m climbed minus 1m slipped down).
To climb a total of 10m, the ant will need to make 10 moves, as 10 moves x 1m per move = 10m.
Therefore, the ant will require 10 moves to reach the top of the 10m high pipe.