What is the element whose 2+ cation's highest energy electron has the following set of quantum numbers, n=5, l=2, ml=1, and m.s=+1/2 for its highest energy electron?
I know, based on the quantum numbers, that its referring to a 5d sublevel. Is it Ba?
How can I find the solution?
Thanks
I don't think the answer is Ba. I agree it is a 4d electron for l = 2
then what is it?
Apply the same reasoning to the Co question that we now know is the correct way to look at the problem.
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To find the element whose 2+ cation's highest energy electron has the given set of quantum numbers, we need to determine which atom would have this electron configuration. Here's a step-by-step guide on how to find the solution:
1. Start by determining the electron configuration of a neutral atom with the given quantum numbers.
- The quantum numbers state n=5, l=2, ml=1, and m.s=+1/2.
- The value of n corresponds to the principal quantum number, which indicates the energy level of the electron.
- The values of l, ml, and m.s correspond to the orbital quantum numbers, which provide information about the shape and orientation of the electron's orbital.
2. Based on the given quantum numbers, we can determine that the highest energy electron is in a 5d orbital.
3. Next, determine the electron configuration for a neutral atom with a 5d electron.
- The electron configuration for a neutral atom with a 5d electron is written as [Xe] 5d^1.
- The [Xe] refers to the electron configuration of the noble gas xenon, which represents the filled inner energy levels before the 5d orbital.
4. Finally, determine the electron configuration for the 2+ cation of the atom.
- When forming a 2+ cation, the atom loses two electrons.
- For the 2+ cation of an atom with a 5d^1 electron configuration, it becomes [Xe] 5d^0.
5. Now that we have the electron configuration for the 2+ ion, we can determine the element by looking for an element whose neutral atom has the same electron configuration.
- If we compare the electron configuration of the 2+ cation ([Xe] 5d^0) with the periodic table, we find that the element with this electron configuration is Tungsten (W).
Therefore, the element whose 2+ cation's highest energy electron has the quantum numbers n=5, l=2, ml=1, and m.s=+1/2 is Tungsten (W), not Barium (Ba).