The index of refraction of water is 1.33. What would be the speed of a light wave passing through at this medium?
4 x 10^8 m/s
2.3 x 10^8 m/s
4.4 x 10^-9 m/s
2.6 x 10-^9 m/s
Refractive Index = (Speed of light in vacuum)/(Speed of light in medium)
Speed of light in vacuum = 3 x 10^8 m/s
Refractive Index = 1.33
1.33 = (3 x 10^8)/(x)
Solve for x.
To calculate the speed of light in a medium, you can use the formula:
v = c / n
where v represents the speed of light in the medium, c represents the speed of light in a vacuum (approximately 3 x 10^8 m/s), and n represents the index of refraction of the medium.
In this case, since the medium is water and the index of refraction of water is 1.33, we can substitute these values into the formula:
v = (3 x 10^8 m/s) / 1.33
Now, let's calculate the speed of light in water using this formula:
v = (3 x 10^8 m/s) / 1.33 ≈ 2.26 x 10^8 m/s
Therefore, the correct answer is approximately 2.3 x 10^8 m/s.