A sample of a new plant food, "super gro", was analyzed. Determine the amount of grams of P and P2O5 as well as the percentage of P2O5 in a sample of "super gro".

Mass of plant food sample: 12.50 grams
Mass of MgNH4PO46H2O recovered: 8.93 grams

mm = molar mass.

am = atomic mass.

grams P = grams MgNH4PO4.6H2O x (am P/mm MgNH4PO4.6H2O) = ?
Then % P = (grams P/mass sample)*100 =- ?

grams P2O5 = grams P x (mm P2O5/am P) = ?
Then % P2O5 =-(grams P2O5/mass sample)*100 = ?

Post your work if you get stuck.

To determine the amount of grams of P and P2O5 in the sample of "super gro" and the percentage of P2O5, we need to follow these steps:

1. Calculate the amount of P in grams:
- Look for the molar mass of MgNH4PO46H2O (magnesium ammonium phosphate hexahydrate):
- The molar mass of MgNH4PO46H2O is 245.41 g/mol.
- Determine the moles of MgNH4PO46H2O:
- Moles of MgNH4PO46H2O = Mass of MgNH4PO46H2O recovered / Molar mass of MgNH4PO46H2O.
= 8.93 g / 245.41 g/mol.
- Since each mole of MgNH4PO46H2O contains 1 mole of phosphorus (P), the amount of P in grams is the same as the moles of MgNH4PO46H2O.

2. Calculate the amount of P2O5 in grams:
- Since each mole of MgNH4PO46H2O contains 2 moles of P2O5 (diphosphorus pentoxide), we need to convert the moles of MgNH4PO46H2O to moles of P2O5:
- Moles of P2O5 = 2 * Moles of MgNH4PO46H2O.
- Now, calculate the mass of P2O5:
- Mass of P2O5 = Moles of P2O5 * Molar mass of P2O5.
- The molar mass of P2O5 is 141.944 g/mol.

3. Calculate the percentage of P2O5:
- The percentage of P2O5 in the sample is the mass of P2O5 divided by the mass of the sample, multiplied by 100:
- Percentage of P2O5 = (Mass of P2O5 / Mass of sample) * 100.

Now let's plug in the values to calculate them:

1. Mass of plant food sample: 12.50 grams
2. Mass of MgNH4PO46H2O recovered: 8.93 grams
3. Molar mass of MgNH4PO46H2O: 245.41 g/mol
4. Molar mass of P2O5: 141.944 g/mol

- Calculate the amount of P in grams:
Moles of MgNH4PO46H2O = 8.93 g / 245.41 g/mol = 0.0363 mol
Mass of P = Moles of MgNH4PO46H2O = 0.0363 mol = 0.0363 g

- Calculate the amount of P2O5 in grams:
Moles of P2O5 = 2 * Moles of MgNH4PO46H2O = 2 * 0.0363 mol = 0.0726 mol
Mass of P2O5 = Moles of P2O5 * Molar mass of P2O5 = 0.0726 mol * 141.944 g/mol = 10.31 g

- Calculating the percentage of P2O5:
Percentage of P2O5 = (Mass of P2O5 / Mass of sample) * 100
= (10.31 g / 12.50 g) * 100
= 82.48% P2O5

Therefore, the amount of grams of P in the sample is 0.0363 grams, the amount of grams of P2O5 is 10.31 grams, and the percentage of P2O5 in the sample is 82.48%.