H2O2 + KI = I2 + KOH
IS this correct for a redox reactions?
what does H2SO4 + Sugar turn into? from a redox reaction standpoint?
the second one is H2SO4 + Sugar and KClO4
Yes, second, I dont understand the reaction.
I know it is some sort of fire, but I don't know how that goes into an equation.
sulfuric + sugar https://www.youtube.com/watch?v=zg9wmU7Z-6s
same reaction, but KClO3 accelerates it (supplies Oxygen to reaction) https://www.youtube.com/watch?v=onmhXRkb53s DO NOT TRY THIS AT HOME.
Looks like carbon is left.
Thank you
To determine if a chemical equation represents a redox reaction, we need to compare the oxidation states of the elements before and after the reaction.
In the first equation:
H2O2 + KI = I2 + KOH
We can assign oxidation states as follows:
- In H2O2, hydrogen (H) has an oxidation state of +1, and oxygen (O) has an oxidation state of -1.
- In KI, potassium (K) has an oxidation state of +1, and iodine (I) has an oxidation state of -1.
After the reaction:
- In I2, iodine has an oxidation state of 0.
- In KOH, potassium has an oxidation state of +1, oxygen in OH has an oxidation state of -2, and hydrogen in OH has an oxidation state of +1.
Comparing the oxidation states before and after the reaction, we see that:
- Hydrogen (H) is reduced from +1 to +1 (no change in oxidation state).
- Oxygen (O) is reduced from -1 to -2 (oxidized).
Since there is a change in the oxidation state of at least one element in the reaction, this equation represents a redox reaction.
In the second equation:
H2SO4 + Sugar
Without specifying the type of sugar, it is challenging to determine the exact reaction and its redox nature. However, generally, when sugar reacts with sulfuric acid (H2SO4), the sugar undergoes dehydration, producing carbon (C) and water (H2O). This reaction is not strictly a redox reaction as there is no clear change in oxidation states.