Find the area of the figure. Round to the nearest tenth if necessary.
L(3,6), M(7,3), N(6,-1), J(2,-1), K(3,3)
Draw the figure. It is a parallelogram with base 4 and height 4
and a right triangle with base 4 and height 3
Surely you can figure those two areas...
Hi Jonathan,
First things first, graph these points. Google desmos calculator, click on the plus sign on the upper left and choose table and insert the points, do not put the letters.
For funsies, I went ahead and did it. You get an irregular figure, it is composed of a parallelogram and a triangle. So this is freaking easy, find the area of the parallelogram ( A = b x h) plus the area of the triangle ( A = (base x height)/2))
Woop, there it is! Hopefully I helped!!! Good luck.
Thank you!!
cdgd
To find the area of the figure formed by the given coordinates (L, M, N, J, and K), we can use the Shoelace Formula. This formula calculates the area of a polygon by taking the sum of the products of the x-coordinates of consecutive points minus the sum of the products of the y-coordinates of consecutive points, divided by 2.
So let's calculate the area using the Shoelace Formula step-by-step:
1. Write down the given coordinates in clockwise order: L(3,6), M(7,3), N(6,-1), J(2,-1), K(3,3).
2. Multiply the x-coordinate of each point with the y-coordinate of the next point, and add up the results:
(3 * 3) + (7 * -1) + (6 * -1) + (2 * 3) + (3 * 6) = 9 - 7 - 6 + 6 + 18 = 20.
3. Multiply the y-coordinate of each point with the x-coordinate of the next point, and add up the results:
(6 * 7) + (3 * 6) + (-1 * 2) + (-1 * 3) + (3 * 3) = 42 + 18 - 2 - 3 + 9 = 64.
4. Subtract the sum of the second step from the sum of the third step: 64 - 20 = 44.
5. Divide the result by 2: 44 / 2 = 22.
Therefore, the area of the figure formed by the given coordinates is 22 square units.