A block of mass 10kg moves horizontal with speed 1.5m/s .if constant vertical force 10N acts,the displacement of block from application of force at end of 4second is?
the horizontal speed continues, so the horizontal displacement is 6m.
vertical displacement is
d=vi*t+1/2 a t^2 where vi=0, a= force/mass=10/10=1m/s^2
d= 1/2 *1*16=8m
displacment = 6horizontal+8up
and that is a 3,4,5 triangle, so the magnitude is 10 at an angle of arctan(4/3)