If 4.39 g AlCl3 is dissolved in enough water to make exactly 100.0ml of a solution, what is the molar concentration of the chloride ion?
the molar mass of AlCl3 is ... 133.3 g
the molarity of the Cl is three times the molarity of AlCl3
divide the sample mass by the molar mass to find the moles in solution
molarity is moles per liter , so the chloride ion molarity is 30 times the moles in solution
Well, let's take a closer look at the situation. We have 4.39 g of AlCl3 dissolved in 100.0 ml of water. The molar mass of AlCl3 is 133.34 g/mol. So, to find the molar concentration of the chloride ion, we need to calculate the moles of AlCl3 and then divide it by the volume of the solution.
First, let's convert the mass of AlCl3 to moles. We know that 1 mole of AlCl3 is 133.34 g, so:
4.39 g AlCl3 * (1 mol AlCl3 / 133.34 g AlCl3) = 0.033 moles AlCl3
Now, let's find the molar concentration of the chloride ion. Since 1 mole of AlCl3 produces 3 moles of chloride ions (Cl-), we can say that the moles of Cl- are:
0.033 moles AlCl3 * (3 moles Cl- / 1 mole AlCl3) = 0.099 moles Cl-
Finally, we divide the moles of Cl- by the volume of the solution (100.0 ml = 0.100 L) to get the molar concentration:
0.099 moles Cl- / 0.100 L = 0.99 M
So the molar concentration of the chloride ion is 0.99 M.
To find the molar concentration of the chloride ion, we need to calculate the number of moles of AlCl3 and then divide it by the volume of the solution.
Step 1: Convert grams of AlCl3 to moles.
The molar mass of AlCl3 is:
Al: 26.98 g/mol
Cl: 35.45 g/mol x 3 = 106.35 g/mol
Total: 26.98 g/mol + 106.35 g/mol = 133.33 g/mol
Number of moles of AlCl3 = (4.39 g) / (133.33 g/mol)
= 0.0329 mol
Step 2: Calculate the volume of the solution in liters.
The given volume is in milliliters (ml), so we need to convert it to liters.
100.0 ml = 100.0 ml x (1 L / 1000 ml)
= 0.1000 L
Step 3: Calculate the molar concentration of the chloride ion.
Molar concentration = Number of moles / Volume of solution in liters
Molar concentration of chloride ion = 0.0329 mol / 0.1000 L
= 0.329 M
Therefore, the molar concentration of the chloride ion is 0.329 M.
To find the molar concentration of the chloride ion, we need to determine the number of moles of chloride ions in the solution. Here's how you can calculate it:
Step 1: Convert the mass of AlCl3 to moles.
The molar mass of AlCl3 is calculated by adding the atomic masses of its constituent elements: Al (26.98 g/mol) and Cl (35.45 g/mol) multiplied by three, since there are three chloride ions in one molecule of AlCl3.
Molar mass of AlCl3 = (26.98 g/mol) + (35.45 g/mol x 3) = 133.33 g/mol
Now, we can calculate the number of moles of AlCl3 by dividing the given mass by its molar mass:
Number of moles of AlCl3 = mass of AlCl3 / molar mass of AlCl3
Number of moles of AlCl3 = 4.39 g / 133.33 g/mol = 0.0329 mol
Step 2: Determine the ratio of chloride ions to AlCl3.
In AlCl3, there are three chloride ions (Cl^-) for every one molecule of AlCl3.
Step 3: Calculate the number of moles of chloride ions (Cl^-).
To find the number of moles of chloride ions, multiply the number of moles of AlCl3 by the ratio of chloride ions to AlCl3:
Number of moles of Cl^- = moles of AlCl3 x (3 moles of Cl^- / 1 mole of AlCl3)
Number of moles of Cl^- = 0.0329 mol x (3 moles of Cl^- / 1 mole of AlCl3) = 0.0987 mol
Step 4: Calculate the molar concentration of chloride ions.
Molar concentration (M) is defined as moles of solute per liter of solution. Since we know the final volume of the solution is 100.0 ml (0.100 L):
Molar concentration of chloride ions = moles of Cl^- / volume of solution in liters
Molar concentration of chloride ions = 0.0987 mol / 0.100 L = 0.987 M
Therefore, the molar concentration of the chloride ion in the solution is 0.987 M.