theoretically, how much iodoform could be prepared from 25ml of 95% ethanol(sp. gr. 0.79)?
Jen, didn't I do this last week for you?
CHI3 from C2H5OH + I2???
Mass C2H5OH available:
25*.95*.79= 18.7grams
moles C available: 18.7/12=1.56
moles CHI3 that can be made "theoretically"= 1.56
Yes, I answered this March 24 at 9:10 P.M.
To determine the amount of iodoform that can be prepared from a given amount of ethanol, we need to calculate the number of moles of ethanol and then use stoichiometry to find the number of moles of iodoform that can be formed. Here's how you can do it:
Step 1: Calculate the mass of ethanol using its volume and density.
First, convert the volume of ethanol from milliliters (mL) to liters (L):
25 mL ÷ 1000 = 0.025 L
Next, calculate the mass of ethanol using its volume and density:
Mass = Volume × Density
Mass of ethanol = 0.025 L × 0.79 g/mL = 0.01975 g
Step 2: Convert the mass of ethanol to moles.
To convert grams to moles, we need to use the molar mass of ethanol, which is 46.07 g/mol.
Number of moles of ethanol = Mass ÷ Molar Mass
Number of moles of ethanol = 0.01975 g ÷ 46.07 g/mol = 0.000428 mol
Step 3: Determine the stoichiometric ratio between ethanol and iodoform.
The balanced chemical equation for the formation of iodoform from ethanol is:
4 CH3CH2OH + 9 I2 + NaOH → 4 CHI3 + Na2CO3 + 7 H2O
From the equation, we can see that 4 moles of ethanol react to form 4 moles of iodoform.
Step 4: Calculate the number of moles of iodoform that can be formed.
Since the stoichiometric ratio is 4:4, the number of moles of iodoform that can be formed is equal to the number of moles of ethanol:
Number of moles of iodoform = Number of moles of ethanol = 0.000428 mol
Step 5: Calculate the mass of iodoform that can be formed.
To calculate the mass of iodoform formed, we multiply the number of moles by the molar mass of iodoform, which is 393.73 g/mol:
Mass of iodoform = Number of moles × Molar Mass
Mass of iodoform = 0.000428 mol × 393.73 g/mol = 0.168 g
Therefore, theoretically, you can prepare approximately 0.168 grams of iodoform from 25 mL of 95% ethanol.