For this equation here: H2SO4 + 2NaOH = 2H2O + Na2SO4
What is the theoretical yield of Na2SO4, in grams?
Cris, please use the same screen name with your posts.
You need some numbers to find the theoretial yield and I don't see any amounts. After you look at your problem and find the amounts, just follow the same procedure in you post as Anonymous.
To find the theoretical yield of Na2SO4 in grams, we need to know the balanced chemical equation and the molar masses of the compounds involved.
The balanced chemical equation is:
H2SO4 + 2NaOH = 2H2O + Na2SO4
First, we need to determine the molar masses of the compounds involved:
- The molar mass of H2SO4 (sulfuric acid) is 98.09 g/mol (2 H atoms x 1.01 g/mol + 1 S atom x 32.07 g/mol + 4 O atoms x 16.00 g/mol).
- The molar mass of NaOH (sodium hydroxide) is 39.99 g/mol (1 Na atom x 22.99 g/mol + 1 O atom x 16.00 g/mol + 1 H atom x 1.01 g/mol).
- The molar mass of Na2SO4 (sodium sulfate) is 142.04 g/mol (2 Na atoms x 22.99 g/mol + 1 S atom x 32.07 g/mol + 4 O atoms x 16.00 g/mol).
From the balanced equation, we can see that one mole of H2SO4 reacts with 2 moles of NaOH to produce 1 mole of Na2SO4. Therefore, the molar ratio of H2SO4 to Na2SO4 is 1:1.
Assuming we have a known quantity of H2SO4 (let's call it "x" moles), the number of moles of Na2SO4 produced will also be "x" moles, based on the 1:1 molar ratio.
To convert the moles of Na2SO4 to grams, we multiply the number of moles by the molar mass of Na2SO4:
Grams of Na2SO4 = moles of Na2SO4 * molar mass of Na2SO4
Therefore, the theoretical yield of Na2SO4, in grams, is:
Theoretical yield = x moles of H2SO4 * (molar mass of Na2SO4 / molar mass of H2SO4)
Since the equation doesn't provide the initial moles of H2SO4, it is not possible to calculate the theoretical yield without that information.