Calculat the weight of KMnO4 in GMs necessary to prepare 250ml of N/10 KMnO4 solution
The truth is that you CAN NOT calculate this without knowing the reaction you're dealing with. Generally, however, KMnO4 is used in acid solution where the equivalent weight is 1/5 the molar mass.
What is a GM? gram mols. I'm not sure i know what a GM is but here is how you prepare 250 mL of a 1/10 N KMnO4 solution.
molar mass is approx 158 (just an estimate so you need to recalculate that). Then the equivalent weight is approx 158/5 = appprox 32.
So you will need 0.1 x 0.250 = approx 0.025 equivalents.
0.025 x equivalent weights x 32 = ? in grams.
Post your work if have follow up questions.
To calculate the weight of KMnO4 in grams necessary to prepare a 250 ml N/10 KMnO4 solution, we need to follow these steps:
Step 1: Understand the given information.
- N/10 KMnO4 solution means normality of KMnO4 is 1/10 or 0.1 N.
- The volume of the solution required is 250 ml.
Step 2: Find the equivalent weight of KMnO4.
The equivalent weight of KMnO4 (Molecular weight divided by the change in oxidation state per mole of electrons transferred) is 158.03 g/mol.
Step 3: Calculate the number of moles of KMnO4 required.
To find the number of moles, we use the formula:
Moles = Normality × Volume (in liters)
Since we have the volume in milliliters, we need to convert it to liters.
Volume (in liters) = 250 ml ÷ 1000
Now, we can calculate the number of moles:
Moles of KMnO4 = 0.1 N × (250 ml ÷ 1000)
Step 4: Calculate the weight of KMnO4 required.
To find the weight of KMnO4, we multiply the number of moles by the molar mass:
Weight = Moles × Molar mass
Let's calculate the weight of KMnO4 in grams:
Weight of KMnO4 = Moles of KMnO4 × Molar mass of KMnO4
Weight of KMnO4 = (0.1 N × (250 ml ÷ 1000)) × 158.03 g/mol
By evaluating this expression, we can determine the weight of KMnO4 required to prepare a 250 ml N/10 KMnO4 solution.