Find the real and imaginary part of 6¡/(2-¡)²

Pls I need working and answer pls

where do you get those inverted ! symbols? Use i fer petesake!

6i/(2-i) = 6i/(2-i) * (2+i)/(2+i) = 6i(2+i)/(2^2+1^2) = (-6+12i)/5