Are these Equations correct?
1. 2KClO3 = 2KCl + 3O2
2. 1H2C2O4 + 2NaOH = 1Na2C2O4 + 2H2O
3. 2C10H22 + 31O2 = 20CO2 + 22H2O
4. 4H2 + Fe3O4 = 3Fe + 4H2O
5. 4P + 5O2 = 2P2O5
And how were they solved?
All equation are correct and balanced correctly. I don't understand "how were they solved?"
To determine if these equations are correct, we need to balance the equations by making sure that the number of atoms on both sides is the same. Let's go through each equation and check if they are balanced:
1. 2KClO3 = 2KCl + 3O2
- On the left side, we have 2 potassium (K), 2 chlorine (Cl), and 6 oxygen (O) atoms.
- On the right side, we have 2 potassium (K), 2 chlorine (Cl), and 6 oxygen (O) atoms.
This equation is indeed balanced.
2. 1H2C2O4 + 2NaOH = 1Na2C2O4 + 2H2O
- On the left side, we have 2 hydrogen (H), 2 carbon (C), 4 oxygen (O), 2 sodium (Na), and 1 oxygen (O) atoms.
- On the right side, we have 2 hydrogen (H), 2 carbon (C), 4 oxygen (O), 2 sodium (Na), and 1 oxygen (O) atoms.
This equation is also balanced.
3. 2C10H22 + 31O2 = 20CO2 + 22H2O
- On the left side, we have 20 carbon (C), 44 hydrogen (H), and 62 oxygen (O) atoms.
- On the right side, we have 20 carbon (C), 44 hydrogen (H), and 62 oxygen (O) atoms.
This equation is balanced.
4. 4H2 + Fe3O4 = 3Fe + 4H2O
- On the left side, we have 8 hydrogen (H), 1 iron (Fe), and 4 oxygen (O) atoms.
- On the right side, we have 8 hydrogen (H), 3 iron (Fe), and 4 oxygen (O) atoms.
This equation is not balanced. To balance it, we need to multiply the iron (Fe3O4) on the left side by 3, giving us:
4H2 + 3Fe3O4 = 9Fe + 4H2O
5. 4P + 5O2 = 2P2O5
- On the left side, we have 4 phosphorus (P) and 10 oxygen (O) atoms.
- On the right side, we have 4 phosphorus (P) and 10 oxygen (O) atoms.
This equation is balanced.
So, after balancing the equations, we can see that equation 4 needed modification to become balanced.