A telephone pole that is 14ft y’all has fallen against a house. If the top of the telephone pole touches the house 8ft. Above the ground, what is the angle that the telephone pole makes with the ground?

Stuck on this question on my quiz not sure how I should set this up or do it, help please :(

Your correct equation would have been

sinØ = 8/14

then on my calculator ....
2nd F
sin
(8÷14)
=
to get appr 34.8°

I tried different combinations, and have no idea how you got 57.

istg what about 10ft off the ground aaa help

You will see a right-angled triangle.

You must know the basic trig ratios in terms of adjacent, opposite and hypotenus

in your triangle , in terms of the base angle , the hypotenuse is 14 and the opposite is 8

what trig ration uses "hypotenuse" and "opposite" ?

Sin. But the answer I get is 57. And the option only contains

29.7
55.2
60.3
34.8

I apologize I guess I entered it wrong. Thank you for your help

Well, that's quite the pickle! But fear not, for Clown Bot is here to add a little laughter to your math struggles.

Let's see if we can solve your problem. We have a fallen telephone pole that is 14ft tall, and the top of the pole is 8ft above the ground where it touches the house. We want to find the angle that the pole makes with the ground.

To begin, we can visualize a right triangle. The height of the telephone pole forms the vertical side, while the distance from the house to the base of the pole becomes the horizontal side. The hypotenuse of this right triangle would then represent the length of the telephone pole.

Now, using the Pythagorean theorem (a^2 + b^2 = c^2), where a and b are the legs of the triangle and c is the hypotenuse, we can set up an equation.

In this case, a = 8ft (height of the pole on the house) and c = 14ft (total height of the pole). We need to find b, the distance from the house to the base of the pole.

8^2 + b^2 = 14^2

64 + b^2 = 196

Subtracting 64 from both sides:

b^2 = 132

Now, taking the square root of both sides:

b ≈ √132

Approximately, b ≈ 11.49ft

Great! Now we know that the distance from the house to the base of the pole is approximately 11.49ft.

To find the angle, we can use the tangent function:

tan(angle) = opposite/adjacent

In this case, the opposite side is 8ft (height of the pole on the house), and the adjacent side is 11.49ft (horizontal distance).

angle = tan^(-1)(8/11.49)

After doing the calculations, we find that the angle is approximately 36.74 degrees.

So, the angle the telephone pole makes with the ground is approximately 36.74 degrees.

Now, go out there and conquer that quiz! And remember, if all else fails, just laugh it off like a clown! 🤡

To solve this problem, you can use trigonometric ratios, specifically the tangent function. The tangent of an angle can be found by dividing the length of the side opposite the angle by the length of the adjacent side.

Here are the steps to solve the problem:

1. Draw a right triangle to represent the situation. The vertical side of the triangle represents the telephone pole, and the horizontal side represents the distance between the house and the bottom of the pole. The hypotenuse represents the distance between the top of the pole and the bottom of the pole.

|
|
------------- <- This represents the house
|
------------- <- The pole leaning against the house
|
|
|
|
------ <- The ground

2. Label the vertical side (telephone pole) as "a," the horizontal side (distance to the house) as "b," and the hypotenuse (distance from pole top to the bottom of the pole) as "c."

We know that a = 14 ft (the height of the telephone pole) and b = 8 ft (the distance from the top of the pole to the house).

|
|
-------------
| a = 14 ft
-------------
| b = 8 ft
|
|
|
|
------

3. We want to find the angle that the telephone pole makes with the ground, which we can denote as angle θ.

4. Recall that the tangent of an angle θ is equal to the ratio of the opposite side to the adjacent side (tan θ = opposite/adjacent). In this case, the tangent can be given as a/b.

tan θ = a/b = 14/8 = 7/4

5. Take the inverse tangent (arctan) of both sides to find the angle θ:

θ = arctan(7/4) ≈ 60.94 degrees

Therefore, the angle that the telephone pole makes with the ground is approximately 60.94 degrees.