Wallace has a $500 budget for a pizza party. Pizzas cost $12 each. He will also purchase drinks for $30, paper plates for $15 and napkins for $6. Write and solve an inequality that shows how many pizzas Wallace can purchase.
12p + 30 + 15 + 6 >- 500
To write an inequality that shows how many pizzas Wallace can purchase, let's start by breaking down the cost of the different items:
Cost of pizzas = $12
Cost of drinks = $30
Cost of paper plates = $15
Cost of napkins = $6
Let's assume Wallace can purchase "x" number of pizzas.
The total cost can be calculated by:
Total Cost = (Cost of pizzas * x) + Cost of drinks + Cost of paper plates + Cost of napkins
Total Cost = (12 * x) + 30 + 15 + 6
We want the total cost to be less than or equal to Wallace's budget, which is $500. Therefore, the inequality can be written as:
(12 * x) + 30 + 15 + 6 ≤ 500
To solve this inequality, we can simplify it:
12x + 51 ≤ 500
Subtracting 51 from both sides:
12x ≤ 449
Dividing both sides by 12:
x ≤ 37.4167
Since Wallace cannot purchase a fraction of a pizza, the maximum number of pizzas he can purchase is 37.
Therefore, the inequality that shows how many pizzas Wallace can purchase is x ≤ 37.