Hello I hope that you are having great evening. I do need a bit of help on the below math problem please.
There are 12 pieces of fruit in a bowl. Seven of the pieces are apples and two are peaches. What is the probability that a randomly selected piece of fruit will not be an apple or a peach. Justify your answer.
How do I do this one?
Thank you
find the prob(apple or peach) , (similar to the previous question)
the prob NOT apple or peach = 1 - prob(apple or peach)
Hello Reiny,
Well 7 are apples and 2 pieces of fruit are peaches. This basically leaves 3 pieces of fruit that are neither apple or peach. So my answer would be as follows
3/12 = 1/4. you'll have a 25 percent chance because 75 percent is the apples and peaches -Is this correct?
Reiny I am new at this an just learning this a bit so I am not very good at this.
Your are correct, I agree with your answer.
Acceptable answers: 1/4, .25, or 25%
Hello! I'd be happy to help you with this math problem.
To find the probability of a randomly selected piece of fruit not being an apple or a peach, we first need to determine how many pieces of fruit in the bowl are neither apples nor peaches.
Out of the 12 pieces of fruit in the bowl, we know that there are 7 apples and 2 peaches. So, to find the number of pieces that are neither apples nor peaches, we subtract the sum of the apples and peaches from the total number of fruit:
12 - (7 + 2) = 12 - 9 = 3
Therefore, there are 3 pieces of fruit in the bowl that are neither apples nor peaches.
Now, to calculate the probability, we divide the number of desired outcomes (fruit that is neither an apple nor a peach) by the number of possible outcomes (total number of fruits):
Probability = (Number of desired outcomes) / (Total number of outcomes)
Probability = 3 / 12
Simplifying the fraction, we get:
Probability = 1 / 4
Therefore, the probability that a randomly selected piece of fruit will not be an apple or a peach is 1/4 or 25%.
I hope this explanation helps! Let me know if you have any further questions.