brandy wants to buy a digital camera that costs $300. supposeshe saves $15 each week, in how many weeks will she have enough money for the camera? use a bar diagram to solve arithmetically, then use an equation to solve algebraically

15w = 300

($15/wk) x #wks = $300

#wks = 300/15 = ?

To solve this problem using a bar diagram arithmetically, we can represent Brandy's progress in saving money each week towards buying the camera.

Step 1: Set up a bar diagram with two bars.
- The first bar represents the cost of the camera, which is $300.
- The second bar represents the total amount of money Brandy has saved.

Step 2: Start with the second bar at zero and label it as $0.

Step 3: Add $15 to the second bar each week, representing the amount Brandy saves.

Step 4: Continue adding $15 to the second bar each following week until it reaches or exceeds $300.

Step 5: Count the total number of weeks it takes for the second bar to reach or exceed $300. This will be the answer to our question.

For example, after 1 week, the second bar will be at $15. After 2 weeks, it will be at $30, and so on.

Using the equation to solve algebraically:
Let's create an equation to solve for the number of weeks it will take Brandy to save enough money for the camera.

Let x represent the number of weeks Brandy saves money. We know that Brandy saves $15 per week, so the equation becomes:

15x = 300

Now we solve for x:

x = 300 / 15

x = 20

Therefore, Brandy will need 20 weeks to save enough money for the camera.