How do you solve this expression \sqrt[8]{v^{40}}!!! So basically it's v^40 divided by 8!!! When I typed v^5 on my homework it said that it was incorrect!!! I want to know what I did wrong!!! Pleaseeeeeeee helpppppppp!!! :(
I read \sqrt[8]{v^{40}} as (√8)(v^40)
In no way can that be interpreted as (v^40) ÷ 8 , I don't
even see a division sign in your expression
retype your expression without all those strange brackets
use v^40 to mean "v raised to the 40"
are you taking the square root of the whole thing, or just of 8 as you typed ?
I'm taking the square root of the whole thing!!! The problem is suppose to look something like this 8^√v^40!!! So 40 is inside of the square root thing and 8 is outside of the square root thing.
8^√v^40 or 8^√(v^40)
that would be 8^(v^2)
To solve the expression \sqrt[8]{v^{40}}!!!, we need to follow a specific order of operations. Let's break it down step by step:
Step 1: Simplify the exponent within the radical.
The expression \sqrt[8]{v^{40}} can be broken down as follows:
\sqrt[8]{v^{40}} = (v^{40})^{1/8} = v^{40 \cdot \frac{1}{8}} = v^5
So, the result should indeed be v^5.
Now let's address the issue you mentioned. If you typed v^5 on your homework and it was marked incorrect, there might be another mistake. Double-check the instructions, guidelines, or requirements given for the specific problem. Pay attention to any particular formatting or notation needed.
If you are still uncertain about the error, it would be best to consult your teacher or professor for clarification.