Calculate the moles of NH3 produced when 0.75 moles of N2 react.
Answer
Calculate the moles of NH3 produced when 0.75moles of N2 react
Calculate the moles of NH3 produced when 0.75 moles of N2 react.
I want a full working out for this question
Calculate the moles of NH3 produced when 0.75 moles of N2 react
I want a full working out for this question
To calculate the moles of NH3 produced when 0.75 moles of N2 react, we first need to determine the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between N2 and NH3 is as follows:
N2 + 3H2 → 2NH3
From the equation, we can see that 1 mole of N2 reacts to form 2 moles of NH3.
Therefore, to find the moles of NH3 produced when 0.75 moles of N2 react, we can use the ratio between N2 and NH3:
0.75 moles of N2 x (2 moles of NH3 / 1 mole of N2) = 1.5 moles of NH3
So, 0.75 moles of N2 will produce 1.5 moles of NH3.