The value of ΔH° for the reaction below is -1107 kJ:

2Ba (s) + O2 (g) → 2BaO (s)

How many kJ of heat are released when 5.75 g of BaO (s) is produced?

[5.75 / (molar mass BaO)] (1107 / 2)

To find the heat released, we need to use the stoichiometry of the reaction and the given value of ΔH°.

First, we need to calculate the number of moles of BaO produced:
1 mol BaO = molar mass of BaO

The molar mass of BaO can be calculated as follows:
molar mass of BaO = atomic mass of Ba + atomic mass of O
= (2 x atomic mass of Ba) + (1 x atomic mass of O)

The atomic masses of Ba and O are found on the periodic table. After calculating, we find that the molar mass of BaO is X g/mol.

Next, we can calculate the number of moles of BaO produced using the given mass of BaO:
moles of BaO = mass of BaO / molar mass of BaO

Substituting in the values, we have:
moles of BaO = 5.75 g / X g/mol

Now that we know the number of moles of BaO, we can use the stoichiometry of the reaction to find the heat released:
ΔH° = -1107 kJ
moles of BaO = X mol
kJ of heat released = moles of BaO * ΔH°

Substituting in the values, we have:
kJ of heat released = (5.75 g / X g/mol) * -1107 kJ

By solving the equation, we can calculate the kJ of heat released when 5.75 g of BaO is produced using the given value of ΔH°.

To determine the amount of heat released when a certain mass of a substance is produced, we can use stoichiometry and the enthalpy change of the reaction.

First, let's find the molar mass of BaO (barium oxide):
Ba: atomic mass = 137.33 g/mol
O: atomic mass = 16.00 g/mol

Molar mass of BaO:
(1 * Ba) + (1 * O) = 137.33 g/mol + 16.00 g/mol = 153.33 g/mol

Next, we need to convert the mass of BaO (5.75 g) to moles:
moles = mass / molar mass
moles = 5.75 g / 153.33 g/mol ≈ 0.0375 mol

From the balanced equation, we see that for every 2 moles of BaO produced, -1107 kJ of heat is released. Therefore, we can set up a ratio:

2 moles BaO : -1107 kJ
0.0375 moles BaO : x kJ

Using this ratio, we can solve for x (the amount of heat released):
x = (0.0375 moles BaO / 2 moles BaO) * -1107 kJ

x ≈ -20.5 kJ

Therefore, approximately 20.5 kJ of heat are released when 5.75 g of BaO (s) is produced.