The sum of three consecutive integers is negative 147.find the three integers
If the numbers were 1, 2, and 3 that would fit the criteria of three consecutive integers. We know that 1 + 2 + 3 does not equal 147 but it is a starting place.
If you let x be the smallest integer. Then we see the next is one number bigger... so x + 1, and the final integer is two numbers bigger than the first so x + 3
147 = x + x + 1 + x+ 2
and solve for x then sub it back into the three let statements.
-147=3x+3
What to do next
Thank you so much teacher
You are very welcome! Enjoy your day : )
To find the three consecutive integers, let's assume the first integer is represented by "x". Since they are consecutive, the second integer will be "x + 1", and the third integer will be "x + 2".
According to the given information, the sum of these three integers is -147. We can write this information as an equation:
x + (x + 1) + (x + 2) = -147
Simplifying the equation:
3x + 3 = -147
Now, we can isolate "x" by subtracting 3 from both sides of the equation:
3x = -150
Dividing both sides by 3:
x = -50
Now that we have the value of "x", we can find the three consecutive integers:
First integer: -50
Second integer: -50 + 1 = -49
Third integer: -50 + 2 = -48
So, the three integers are -50, -49, and -48.
Take the 3 to the side that has the number...
- 147 = 3x + 3
So if you balance it off
- 147 - 3 = 3x +3 - 3
-150 = 3x
.... and you can solve for x