the sum of the squares of two positive whole number is 792 if one of the numbers is 13 find the other
Let's assume the other positive whole number is "x".
According to the given information, the sum of the squares of the two numbers is 792. This can be expressed as:
x^2 + 13^2 = 792
Simplifying the equation, we have:
x^2 + 169 = 792
Subtracting 169 from both sides, we get:
x^2 = 623
Taking the square root of both sides, we find:
x = √623
Now, let's calculate the value of x:
x ≈ 24.93
Since we are looking for a positive whole number, the other positive whole number is approximately 25.
To find the other number, we can set up an equation based on the given information.
Let's assume the other number is represented by 'x'. According to the problem, the sum of the squares of the two numbers is 792, which can be expressed as:
13^2 + x^2 = 792
Simplifying this equation, we have:
169 + x^2 = 792
Now, we can subtract 169 from both sides:
x^2 = 792 - 169
x^2 = 623
To find the value of 'x', we need to take the square root of both sides:
√(x^2) = √623
x = ± √623
Since we are looking for a positive whole number, we take the positive square root:
x = √623
To get the exact value, we can use a calculator or a mathematical software. The approximate value of √623 is around 24.98. However, since we need a whole number, we round up the value to the nearest whole number.
Therefore, the other positive whole number is approximately 25.
169 + n^2 = 792
n^2 = 623
n is not a whole number. I bet 792 is supposed to be 794